2c^2+cd-d^2=0

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Solution for 2c^2+cd-d^2=0 equation:


Simplifying
2c2 + cd + -1d2 = 0

Reorder the terms:
cd + 2c2 + -1d2 = 0

Solving
cd + 2c2 + -1d2 = 0

Solving for variable 'c'.

Factor a trinomial.
(2c + -1d)(c + d) = 0

Subproblem 1

Set the factor '(2c + -1d)' equal to zero and attempt to solve: Simplifying 2c + -1d = 0 Solving 2c + -1d = 0 Move all terms containing c to the left, all other terms to the right. Add 'd' to each side of the equation. 2c + -1d + d = 0 + d Combine like terms: -1d + d = 0 2c + 0 = 0 + d 2c = 0 + d Remove the zero: 2c = d Divide each side by '2'. c = 0.5d Simplifying c = 0.5d

Subproblem 2

Set the factor '(c + d)' equal to zero and attempt to solve: Simplifying c + d = 0 Solving c + d = 0 Move all terms containing c to the left, all other terms to the right. Add '-1d' to each side of the equation. c + d + -1d = 0 + -1d Combine like terms: d + -1d = 0 c + 0 = 0 + -1d c = 0 + -1d Remove the zero: c = -1d Simplifying c = -1d

Solution

c = {0.5d, -1d}

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